Maritime

Example 2: A vessel steams 040° T.for 2300 miles from position 39°37' S, long. 47° 28'W, .Find the arrival position.

Solution:

1. d.lat. = Dis. x cos. (course)

= 2300 x cos. 40 °

= 1761 .9

= 29°21.9´

2. Initial position = 39 °37' S.

d.lat = 29°21.9´N.

Arrival lat. = 10°15.1´S.

3. M.P. 1 = 2577.82

M.P. 2 = 614.25

D.M.P. = 1963.57´

4. d.long. = D.M.P. x tan. (course)

= 1963.57 x tan. 40°

= 1647 .6

= 27°27.6´

5. Initial long.= 47 °28' W.

d.long.= 27 °27.6´ E.

Final long.= 20 °00.4´W. Ans